x^2+10x=999

Solution for x^2+10x=999 equation:

x^2+10x=999

We move all terms to the left:

x^2+10x-(999)=0

a = 1; b = 10; c = -999;
Δ = b2-4ac
Δ = 102-4·1·(-999)
Δ = 4096
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4096}=64$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-64}{2*1}=\frac{-74}{2}
=-37
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+64}{2*1}=\frac{54}{2}
=27
$